Dividing a catenary curve into equal length parts

149 Views Asked by At

I've got a catenary equation $$y = a\cosh(x/a)$$ and I'm trying to divide it into $n$ segments of equal length to use it in some FEM code. I know the formula for the arc length between two points, but since it involves integration, inverting it seems a little hard. Is there a direct way to find the points on this curve that I want?