If you take $\sqrt{2}$ in base $10$ and remove all digits $2$-$9$ you will get something like $1.1100010010101$... which i believe to be transcendental, and it got me curious, could there be an algebraic irrational number made of just $0$'s and $1$'s? does an algebraic irrational number need to have all digits from the base?
2026-03-27 11:24:35.1774610675
Does an algebraic irrational number always have all digits from the base?
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