How can be written a double series with WolframAlpha where the series are interdependent like, for instance, the following ones? $$\sum_{j=1}^i \sum_{i=2}^n (i^2-j)$$
(I don't get, as expected, a result which depends only on $n$).
2026-03-26 04:51:17.1774500677
Double series with WolframAlpha where the series are interdependent
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If you'd like your answer to depend only on $n$, your sums may be in the wrong order. Plugging in "Sum[i^2-j,{i,2,n},{j,1,i}]" to Wolfram Alpha gives $$ \sum_{i=2}^n \sum_{j=1}^i (i^2-j) = \frac{1}{12} n (n-1)(n+1)(3n+4). $$ If you have the sums set the other way, then $i$ is both a fixed number you're iterating to, as well as a variable you are using as an index. Is this what you're looking for?