the question stated to find the sum of all coefficients divisible by 37 in the expansion of $ (2x+y+z)^{37} $
I proceeded by writing out
$ (2x+y+z)^{37} $ = $ \sum_{0 \le p,q,r \le 37} $ (${ (37!) 2^p \over (p! (q!) (r!)}$ ) $ x^p y^q z^ r $ where p + q + r = 37.
but got stuck at this point