Draw two cards at random without replacement. What is the chance of not getting all kings?

Question

I am at a loss for how to solve this problem. Can someone please help and link the steps below? Thank you so much!

Answer 1

It is easier to compute the chance you get two kings and subtract from $1$. What is the chance the first is a king? The second? Both?

Answer 2

You want the probability for not obtaining two from four kings when selecting two from fifty-two cards without replacement or bias.

Use the law of complementary probability, and subtract from $1$ the probability for obtaining two kings.

Also recall that $\binom mn$ counts ways to select $n$ from $m$ things without replacement or bias.