Let $f(x)=x^2-2 \in \mathbb{Z}_5[x]$.
$f(x)$ is irreducible.
Let $\xi$ be a solution of $f(x)$ in an extension of $\mathbb{Z}_5$.
How can I show that $E=\mathbb{Z}_5(\xi)$ is a splitting field of $f(x)$ ??
Let $f(x)=x^2-2 \in \mathbb{Z}_5[x]$.
$f(x)$ is irreducible.
Let $\xi$ be a solution of $f(x)$ in an extension of $\mathbb{Z}_5$.
How can I show that $E=\mathbb{Z}_5(\xi)$ is a splitting field of $f(x)$ ??
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Since the two roots are $\xi$ and $-\xi$, you have that the splitting field is $\mathbb{Z}_5(\xi, -\xi) = \mathbb{Z}_5(\xi)$.