I'm considering edge percolation on $ℤ^2$ with parameter $p$, so that edges are present with probability $p$ and $\theta_x(p)=P[\lvert C(x)\rvert=∞]$ (where $C(x)$ is the component containing $x$ in the percolation graph).
Is it known that $\theta_x(p)=P[\lvert C(x)\rvert=∞]=P[\lvert C(0)\rvert=∞]$ (where 0 is the origin in $ℤ^2$) and therefore $\theta_x(p)=\theta_y(p)$ $∀ x,y∈ℤ^2$. But how can this be explicitly proven/explained?
For all x,y , there exists an automorphism that sends x on y (the translation for example), so that the probablities are equals.