Elementary Geometry problem - Proving the angles $A'B'C'$ and $\beta$ are the same

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In the above picture, the line t is tangent to the circle at $C'$. How do I prove the angle $A'B'C'$ is equal to the angle $\beta$?

I tried to do a lot of things, like tracing parallels and perpendiculars through points and using theorems of angles to use similarity of triangles or using the outer angle theorem... nothing worked.

Thanks.

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They both intercept the same arc. They are essentially inscribed angles whose measure is one-half the intercepted arc.