In the above picture, the line t is tangent to the circle at $C'$. How do I prove the angle $A'B'C'$ is equal to the angle $\beta$?
I tried to do a lot of things, like tracing parallels and perpendiculars through points and using theorems of angles to use similarity of triangles or using the outer angle theorem... nothing worked.
Thanks.

They both intercept the same arc. They are essentially inscribed angles whose measure is one-half the intercepted arc.