Еquation of the height in triangle

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My task is to find the equation of the height in triangle ABC given the coordinates of the three points. The coordinates of the points are: $A(1, 2), B(-2, 1), C(-1, -2)$. The solution that I wrote is: СН is perpendicular to AB. AB has coordinates (-3, -1). It follows that the equation is -3x -1y + C = 0. Point C (-1, -2) lies on the line. $$ 3*(-1) -1 * (-2) + C = 0$$ $$C = -5$$ The equation of CH is: $$-3x -1y -5=0$$ My question is, is this solution to the problem correct?

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You have neglected the first rule with such questions:

DRAW THE FIGURE!

If you would have done that, you would have realised that you are dealing with a right-angled triangle, which means that two of the sides are heights of the triangle.

This being said, your solution is right, as you can see from this drawing:

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