Is there a way (using statistics, or data analysis) to predict the nth term of a random sequence given the first k terms. For instance, what about predicting the $n$th in this sequence (random, appearing list of primes):
$p_n$ $=$ $2, 3, 11, 17, 23, 53, 79, 103, 197, 593, 971, 1021, 1663, 2099, 3571, 4447, 5419, 10781, 29347, 57901, 78517, 91129, 251893, 695407...$
(all terms less than $1M$ of this specific, random appearing sequence of primes)
Given $p_{24}$ $=$ $695407$ estimate $p_{70}$?
Is there a way to solve this sequence (find $p_n$ given the first 22 terms) with statistics and analyzing the behavior of it. In other words, there is an approximation formula for any single-set of sequcences to find any $n$th term greater than it. Thanks in advance.
Well I can't say I know much on the subject, but given the fact that your sequence is 'random' and strictly of prime numbers less than 1M, there's probably not any way to do what you are asking. Sorry.