Evaluate: $I(x)=\int_0^x\ t^{a}\ (\sin\ t)^{b} dt $

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I would calculate (by using a series of functions probably) this integral:

$$I(x)=\int_0^x\ t^{a}\ (\sin\ t)^{b} dt $$

where $$ x\in\ [0,\frac{\pi}{2}] \ \ \ \ \| \ \ \ a,b \in\mathbb{N}$$

Using the hypergeometric functions:

$$I(x)=\int_0^x\ t^{a+1}\ (\ _0F_1(\frac{3}{2};-\frac{1}{4}t^2)\ )^b \ dt$$

But in this way I do not think it is possible to continue integration

Thanks in advance