Evariste Galois' proof of the "Primitive Element Theorem"

57 Views Asked by At

I've been reading Galois' memoir on the insolvability of the quintic and am trying to understand his reasoning on a lemma which seems to be a version of the primitive element theorem.

In modern language, he supposes $K$ is a number field, $a,b, c, ...$ is a finite collection of algebraic numbers, and $V = \varphi(a,b,c,...)$ is a rational function of $a,b,c,...$ for which

$$\varphi(\sigma(a),\sigma(b),\sigma(c),...) \neq \varphi(a,b,c,...) $$

for any permutation $\sigma$ of $a,b,c,...$. Then, Galois claims that $K(V) = K(a,b,c,...)$.

For example, if $V = \sqrt{2} + 2 \sqrt{3}$, then this says that $\sqrt{2}$ and $\sqrt{3}$ both are polynomial functions of $V$.

I'm not able to follow his reasoning (I will supply a picture of the text soon). He says to look at the product

$$F(V,a) = \prod\limits_{\sigma} (V - \varphi(a,\sigma(b),\sigma(c), ...)) = 0.$$

as $\sigma$ runs through all permutations of $b,c,...$. This product is symmetric in $b, c, d, ...$, so Galois says we should just think of this equation as a function of $V$ and $a$. He then says "we can pull $a$ out of the equation." What does this mean, and why does it follow that $a$ (and likewise, $b, c,$ etc.) can be solved for as a rational expression in $V$?