The two uparrows $\uparrow$ have different meanings.
$A_n \uparrow A$ means that $A_n$ is an increasing sequence of sets, i.e. $A_n \subseteq A_{n+1}$, and the countable union $\cup_{n \in \mathbb{N}} A_n = A$.
$P(A_n) \uparrow P(A)$ means that $P(A_n)$ is an increasing sequence of real numbers, i.e. $P(A_n) \leq P(A_{n+1})$. Since $P(E) \leq 1$, such a sequence converges to $L \in \mathbb{R}$ (why?). Part (a) asks you to show this limit $L$ is indeed $P(A)$.
The downarrows $\downarrow$ are just an analogue in the context of probability.
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Bumbble Comm
On
$A_n \uparrow A$ means $A_m \subseteq A_n$ for $m \leq n$ and $A = \bigcup_{n \in \mathbb{N}}A_n$.
Similarly, $A_n \downarrow A$ means $A_m \supseteq A_n$ for $m \leq n$ and $A = \bigcap_{n \in \mathbb{N}} A_n$.
The two uparrows $\uparrow$ have different meanings.
$A_n \uparrow A$ means that $A_n$ is an increasing sequence of sets, i.e. $A_n \subseteq A_{n+1}$, and the countable union $\cup_{n \in \mathbb{N}} A_n = A$.
$P(A_n) \uparrow P(A)$ means that $P(A_n)$ is an increasing sequence of real numbers, i.e. $P(A_n) \leq P(A_{n+1})$. Since $P(E) \leq 1$, such a sequence converges to $L \in \mathbb{R}$ (why?). Part (a) asks you to show this limit $L$ is indeed $P(A)$.
The downarrows $\downarrow$ are just an analogue in the context of probability.