Expanding $1/[(s^2+1)(s+1)]$ into partial fractions by brute force

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I want to do partial fractions on: $1/[(s^2+1)(s+1)]$

$(as+b)/(s^2+1) + c/(s+1)$

Multiplying both sides by $(s^2+1)(s+1)$, get $a=-1/2, b=1/2, c=1/2$

$(-s/2+1/2)/(s^2+1) + (1/2)/(s+1) = 1/[(s^2+1)(s+1)]$

Unfortunately when I add $(-s/2+1/2)/(s^2+1) + (1/2)/(s+1)$ I get $(1/4)/[(s^2+1)(s+1)]$.

Where did I go wrong?

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No,when you add $$ \frac{-s/2+1/2}{s^2+1} + \frac{1/2}{s+1} $$ you get $$ \frac{1}{2}\frac{1-s^2+1}{(s^2+1)(s+1)} $$ or $$ \frac{1}{(s+1)(s^2+1)}. $$