Let $P(X)$ be an irreducible polynomial in $\mathbb Q[X]$. The field $L = \mathbb Q[X]/(P(X))$ will have at least one root $\alpha$ of $P(X)$ but it may have more.
Can all the other roots $L$ has be expressed as polynomials in $\alpha$ and how are those polynomials computed?
Let $P(X)$ be an irreducible polynomial over $\mathbb Q$ with degree $d$ and pick a root $\alpha$. Let us have the fields $A = \mathbb Q(\alpha)$ and $B$ the splitting field of $P(X)$. $A$ has degree $d$ and is contained in $B$.
If $A = B$ then $P(X)$ splits into linear factors, this is equivalent to the roots being expressible as polynomials in $\alpha$.
$A = B$ happens iff $[B : \mathbb Q] = d$ in other words the Galois group has size d.
Example 1: degree 5 polynomial with group $C_5$
polynomial from https://www.lmfdb.org/NumberField/?hst=List&galois_group=C5&search_type=List
Example 2: degree 4 with group $V_4$
polynomial from https://www.lmfdb.org/NumberField/?hst=List&galois_group=4T2&search_type=List
Non-Example. Degree 6 with group $S_3 \times C_3$.
In this case we get 3 linear factors and then another non-linear factor. I don't know how to characterize this sort of situation.