Expressing $\sum_{k=1}^{n}\frac{1}{(k+2)k!}$ in terms of $n$.

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How would I express $$\sum_{k=1}^{n}\frac{1}{(k+2)k!}$$ in terms of $n$?

An attempt of mine is $$\sum_{k=1}^{n}\frac{1}{(k+2)k!} = \sum_{k=1}^{n}\frac{1}{(k+1)! + k!},$$ which is not useful for me. Is there any established expression for a sum involving factorials in terms of $n$?

An elementary approach is of the first priority, say high-school math.

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$$\frac{1}{(k+2)k!} = \frac{k+1}{(k+2)!} = \frac{1}{(k+1)!} - \frac{1}{(k+2)!}.$$