I know there is a fairly elementary way to factor $n = pq$ (distinct primes) given the value of the totient function, but is there an efficient way to find this if we know $n = pqr$ and we know $\phi(n) = (p-1)(q-1)(r-1)$?
2026-03-28 22:08:28.1774735708
Factoring $n = pqr$ given $\phi(n)$
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