False statements in intuitionistic logic

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In the explanations of intuitionistic logic I've been reading (1, 2, 3), especially in the explanation of the semantics, I don't understand how a proposition being false influences the situation.

These explanations say something like "$W \Vdash p$ iff $p$ is true in $W$". That sounds clear enough, and then they continue and define the other operators. What I don't get is, when $W \not\Vdash p$? In source 3 they later show some diagrams where actually in every world each proposition has a truth value, either 0 or 1, so in that case I guess when $W(p) = 0$ then $W \not\Vdash p$. I feel like, for this to be the case, the explanation should have contained a short line saying, $\Vdash$ is the minimal relation following these definitions, otherwise it would be allowed to have $W \Vdash p$ even though $W(p) = 0$.

However 1 makes me doubt my interpretation for 3, as it contains the following:

you can think of intuitionistic logic as a logic where at a given point of time, a statement can have three truth values: T (top), which means provably true; ⏊ (bottom) which means provably false, and unproved

Following this line of reasoning, whenever $p$ is unproved, you can have neither $\Vdash$ nor $\not\Vdash$. But I feel this would make the definition of negation in 3 useless...? As a computer scientist with only a passing knowledge of formal logic, this is were my brain sputters to a halt.

My questions:

  • Is the explanation in 3 correct in that in a given world, a $p$ is either assigned $0$ or $1$? (This is the case, as stated on slide 27.)
  • Is it a safe way to model intuitionistic logic, or does it exclude true statements/proofs that the description in 1 would allow?
  • What is the canonical source I can read for a a semantics for inuitionistic propositional logic that is broadly accepted as standard (or, at least has some degree of consensus around it)?

(As a side note: 1 seems to skip defining negation for formulas, is that just an oversight or could 3 have skipped defining it, as it is implied by the other definitions?)

Thanks for any explanatations or tips for other reading material!

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You say

“ whenever $p$ is unproved, you can have neither ⊩ nor ⊮.”

This isn’t correct. Consider the Law of the Excluded Middle $A \lor \neg A$. Intuitionistic Logic doesn’t have to have this formula satisfied at an arbitrary world, but that doesn’t mean it has to be false in every world in a given model. That of course would be inconsistent, since Intuitionism proves the double-negated version.

In particular, there is a difference between

$w \not \Vdash p$

and

$w \Vdash \neg p$

as the latter means $v \not \Vdash p$ whenever $w \le v$, while the former simply means the value of $p$ is $0$ at $w$.