Find $\angle ACB$ using the knowledge of cyclic quadrilaterals

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$O$ is the center of the circle

Find $\angle ACB$ It is given that $\angle ABD=50^\circ$ & $\angle ACD=50^\circ$ (inscribed angle theorem)

Can you help me here stating the reasons

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Note that AOD = 100 (2*ABD since angle subtended at center is twice the angle subtended on the arc)

Hence AOB = 80 (since Points D O and B are collinear )

Hence ACB =40 ( angle subtended at center is twice the angle subtended on the arc)

Ps- I am not yet familiar with Mathjax or latex :( Note that ACB,AOB...are all angles