$O$ is the center of the circle
Find $\angle ACB$ It is given that $\angle ABD=50^\circ$ & $\angle ACD=50^\circ$ (inscribed angle theorem)
Can you help me here stating the reasons
$O$ is the center of the circle
Find $\angle ACB$ It is given that $\angle ABD=50^\circ$ & $\angle ACD=50^\circ$ (inscribed angle theorem)
Can you help me here stating the reasons
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Note that AOD = 100 (2*ABD since angle subtended at center is twice the angle subtended on the arc)
Hence AOB = 80 (since Points D O and B are collinear )
Hence ACB =40 ( angle subtended at center is twice the angle subtended on the arc)
Ps- I am not yet familiar with Mathjax or latex :( Note that ACB,AOB...are all angles