find $\angle{BDE}$

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the only thing I could find is this equation: $\angle{BDE}$ + $\angle{CED}$ = 80 . I don't know what to do...

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i have three equations: $$a^2=ED^2+BD^2-2ED\cdot BD\cos(x)$$ $$\frac{\sin(50^{\circ}}{\sin(x)}=\frac{ED}{a}$$ $$\frac{\sin(70^{\circ})}{\sin(80^{\circ})}=\frac{a}{BD}$$