From Probability through problems by Marek Capinski,Jerzy Zastawniak,:
Find $\limsup_{n \to \infty}A_n$ and $\liminf_{n \to \infty}A_n$,where
\begin{eqnarray*} A_n &=&\left(\frac 13-\frac1{n+1},1+\frac 1{n+1}\right) \mbox{ if}\space n=1,3,5,... \\&=&\left(\frac 1{n+1},\frac 23-\frac{1}{n+1}\right) \space\mbox{ if} \space n=2,4,6,...\\ \end{eqnarray*}
We are given definition as:
$\limsup_{n \to \infty}A_n=\cap_{n=1}^{\infty}\cup_{k=n}^{\infty}A_k$
$\liminf_{n \to \infty}A_n=\cup_{n=1}^{\infty}\cap_{k=n}^{\infty}A_k$
I am unable to use this definition to find the $\limsup_{n \to \infty}A_n$ and $\liminf_{n \to \infty}A_n$ of above sequence.Please let me know how can I get the required limits.
Thanks in advance!
A way to characterize $\limsup A_n$ is:$$x\notin\limsup A_n\iff\{n\mid x\in A_n\}\text{ is finite}\tag1$$
A way to characterize $\liminf A_n$ is:$$x\in\liminf A_n\iff\{n\mid x\notin A_n\}\text{ is finite}\tag2$$
Observing that $$\{n\mid x\notin A_n\}\text{ is finite}\implies \{n\mid x\in A_n\}\text{ is infinite}$$ we conclude that: $$\liminf A_n\subseteq\limsup A_n$$
With tools $(1)$ and $(2)$ check out for some $x\in\mathbb R$. This by discerning the following cases: