Can someone help me find a lower bound to the function
$$\ln(1 - 0.5^u), u\ge0$$
I tried to use the Taylor formula, but it didn't seem to work. I would be grateful if anyone could give me some advice.
Can someone help me find a lower bound to the function
$$\ln(1 - 0.5^u), u\ge0$$
I tried to use the Taylor formula, but it didn't seem to work. I would be grateful if anyone could give me some advice.
On
As a general approach you could try to find a minimum point.
$$y=\ln(1-0.5^u).$$
Differentiating,
$$y'=\frac{\log(2)0.5^u}{1-u^{0.5}}.$$
To find stationary points, set equal to zero to obtain
$$0.5^u=0,$$
which has no solutions, so there are no stationary points. Hence, no minimum and so no lower bound.
As $u\rightarrow 0$, the expression tends to $-\infty$, so there is no lower bound.