The term is u^16 v^4
When (u^2 - v^2 ) ^10 is exanded by the binomial theorem.
My book uses Combinations, but I'm not sure if it works if u and v are squared?
The term is u^16 v^4
When (u^2 - v^2 ) ^10 is exanded by the binomial theorem.
My book uses Combinations, but I'm not sure if it works if u and v are squared?
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Put $x=u^2$, $y=v^2$, and you are reduced to looking for the $x^8 v^2$ term in $(x+y)^{10}$. So it makes essentially no difference that there are squares: you'll still get $\binom{10}{8}$ as the answer.