I know that Dom$ (f) = (-\infty,4]$ Dom $(g) = \mathbb{R}$, but the problem is Dom$(f+g)$.
Please also tell Dom$(f-g)$
Since $g(x)=x^2$ does exists for every $x in \mathbb R$ and since $\sqrt{4-x}$ require that $4-x \geq 0$, the Domain of $f+g$ is simply
$$ D = \left\{ {x \in \mathbb{R}:x \geqslant 4} \right\} $$
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Since $g(x)=x^2$ does exists for every $x in \mathbb R$ and since $\sqrt{4-x}$ require that $4-x \geq 0$, the Domain of $f+g$ is simply
$$ D = \left\{ {x \in \mathbb{R}:x \geqslant 4} \right\} $$