Find the equation of an ellipse with eccentricity $\frac{1}{2}$ and distance $24$ between the directrices.
The answer in the book is $$3x^2 + 4y^2 = 108$$
I already know how to get the first and second terms, but how did the constant become $108$?
Find the equation of an ellipse with eccentricity $\frac{1}{2}$ and distance $24$ between the directrices.
The answer in the book is $$3x^2 + 4y^2 = 108$$
I already know how to get the first and second terms, but how did the constant become $108$?
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