Find the minimum value of the perimeter of a triangle whose area is 3 $cm^2$ I tried it using Hero rule $$A = \sqrt{s(s-a)(s-b)(s-c)}$$ $$9 = s(s-a)(s-b)(s-c)$$ But it did not serve me well ?
2026-03-25 22:10:13.1774476613
Find the minimum value of the perimeter
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By AM-GM and by your work we obtain: $$9=s(s-a)(s-b)(s-c)\leq s\left(\frac{s-a+s-b+s-c}{3}\right)^3=\frac{s^4}{27}.$$ Can you end it now?