$Y=e^{X^2}$ , where $X\sim N(0,1)$
I want to find the pdf of $Y$.
Guide:
Find CDF of $Y$ for positive $y$ on base of: $$P(Y\leq y)=P(X^2\leq\ln y)=P(-(\ln y)^{\frac12}\leq X\leq(\ln y)^{\frac12})=2\Phi((\ln y)^\frac12)-1$$
Then find PDF by differentiating.
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Guide:
Find CDF of $Y$ for positive $y$ on base of: $$P(Y\leq y)=P(X^2\leq\ln y)=P(-(\ln y)^{\frac12}\leq X\leq(\ln y)^{\frac12})=2\Phi((\ln y)^\frac12)-1$$
Then find PDF by differentiating.