Let $C$ be the curve with parametric equation $\begin{cases} u(t) = t^2+t \\ v(t) = t^2-t \end{cases}$. Find the point on the graph of $C$ where the slope is $2$.
So far, I've graphed this and it looks like the point is near the origin, but I don't know how to pinpoint the exact point.
hint
Solve the equation $$\frac {v'(t)}{u'(t)}=2$$
or $$\frac {2t-1}{2t+1}=2$$
which gives $$t=-\frac 32$$