$$f(x)=xe^{x^2}$$
$$f(x)= \sum_{n = 0}^{\infty} \frac1{an!}x^{pn}$$
Need to find $an$ and $pn$?
Not sure how to approach this one, even though I have been solving these type of questions before.
$$f(x)=xe^{x^2}$$
$$f(x)= \sum_{n = 0}^{\infty} \frac1{an!}x^{pn}$$
Need to find $an$ and $pn$?
Not sure how to approach this one, even though I have been solving these type of questions before.
You know the Taylor Series for $e^x$:
$$e^x = \sum_{n=0}^\infty {1\over n!} x^n$$
And when multiplying by $x$ and plugging in $x^2$, we get:
$$xe^{x^2} = \sum_{n=0}^\infty x\cdot {1\over n!} \left(x^2\right)^n = \sum_{n=0}^\infty {1 \over \frac 1x n!} x^{2n}$$