find the radius of convergence of the power series $\sum _1^{\infty} n^{-\sqrt n} z^n $
here $a_n= n^{-\sqrt n}\\$
$ \frac{1}{R}=\lim_{n \rightarrow \infty} [ n^{-\sqrt n} ]^\frac{1}{n}$ for further i didnt get any one can help
find the radius of convergence of the power series $\sum _1^{\infty} n^{-\sqrt n} z^n $
here $a_n= n^{-\sqrt n}\\$
$ \frac{1}{R}=\lim_{n \rightarrow \infty} [ n^{-\sqrt n} ]^\frac{1}{n}$ for further i didnt get any one can help
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Hint: $$(n^{-\sqrt{n}})^{1/n}=n^{-1/\sqrt{n}}=e^{\frac{-\log n}{\sqrt{n}}}$$