In the figure, calculate $x$, if $a=1$ and $b=9$ (S:$x=3$)
Relationships that I found
Let $d$ = $BD$
$\triangle BCD: 2x+d = BC+CD$
$d^2=BC^2+CD^2$
$\triangle AED:2.1+AD = AE+ED=AE+BC$
$AD^2 = AE^2+BC^2$
In the figure, calculate $x$, if $a=1$ and $b=9$ (S:$x=3$)
Relationships that I found
Let $d$ = $BD$
$\triangle BCD: 2x+d = BC+CD$
$d^2=BC^2+CD^2$
$\triangle AED:2.1+AD = AE+ED=AE+BC$
$AD^2 = AE^2+BC^2$
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Note that all the triangles, including the three containing the three respective circles, are similar, which establishes the ratios $$\frac xb = \frac ax\implies x= \sqrt{ab}=3$$