How do you find the range of the following function, please?
$$\frac{2x^2 + 20}{x^2 + 5}$$
Hint: $$\frac{2x^2+20}{x^2+5}=2+\frac{10}{x^2+5}$$ and $$0<\frac{10}{x^2+5}\le \frac{10}{0+5}= 2$$
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Hint: $$\frac{2x^2+20}{x^2+5}=2+\frac{10}{x^2+5}$$ and $$0<\frac{10}{x^2+5}\le \frac{10}{0+5}= 2$$