The given sides were $AC=BD=25$, $AD=BC=15$, and $DC=7$. No other explanations were given to this problem.
I tried to connect $A$ and $B$ to form an isosceles trapezoid then tried to work around with similar triangles but found no luck solving it.
The given sides were $AC=BD=25$, $AD=BC=15$, and $DC=7$. No other explanations were given to this problem.
I tried to connect $A$ and $B$ to form an isosceles trapezoid then tried to work around with similar triangles but found no luck solving it.
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Notice, in $\Delta ACD$, $AD+DC=15+7=22<25$ (third side $AC$).
A triangle will exist iff the sum of any two sides is greater than third side. Therefore, $\Delta ACD$ and $\Delta BCD$ do not exist.