I am currently researching on VANET for identifying the road capacity based on vehicle moving speed. Below is my question,
If a car moving on 8km/h and distance to the next car is 15 meters, what will be the time gap or avoidance time estimation it has in case of emergencies?
Can some one help me on this?
So, in case the car in front stops, the time the car behind has to stop is the time it takes to travel 15 meters when driving 8 km/h. This can be found by using the formula
$v = \frac{d}{t}$,
where $v$ is velocity, $d$ is distance, and $t$ is time. By using this formula, we can find the time is takes to travel when distance and velocity are given using
$t = \frac{d}{v}$.
Therefore, the computation is
$t = \frac{\frac{15 m}{1000}}{8 km/h} = 0.001875$, which is 6.75 seconds.