Find triple integral $\iiint_V \sqrt{x^2+y^2}sin(z^2) dxdydz$ when V: $\sqrt{x^2+y^2}\le z \le 3$.
First, I try to change variables $x=rcos\phi,y=rsin\phi,z=z$ but I can't find $\int sin(z^2)dz$. I try to let $z^2=u$ but it doesn't help. I think I have to find some ways to change variables which J ( Jacobi ) include z so I can caculus $\int zsin(z^2)dz$.
But no matter how many times I try, I still can't find the answer. So, can you guys help me with this exercise or give me any ideas? Thank you so much for your help.
In cylindrical coordinates, you have\begin{align}\int_0^{2\pi}\int_0^3\int_0^zr^2\sin(z^2)\,\mathrm dr\,\mathrm dz\,\mathrm d\theta&=2\pi\int_0^3\frac13z^3\sin(z^2)\,\mathrm dz\\&=\frac{1}{3} \pi (\sin (9)-9 \cos (9)).\end{align}Note that you can compute$$\int z^3\sin(z^2)\,\mathrm dz$$doing $z^2=x$ and $2z\,\mathrm dz=\mathrm dx$.