Finding Angle BDF inside a circle

Question

Find Angle BDF

What i tried Since Angle AOE is twice Angle ACE, we have Angle ACE= $(360-214)/2=73$ degrees.

Angle OET and Angle TAO is $90$ degrees since its a tangent line to the circle.

Angle ATE can then be found by taking $360-90-90-146=24$ degrees

Im unsure how to continue from here. Could anyone explain. Thanks

Answer 1

Guide:

• From reflex $\angle AOE$, compute $\angle AFE$.

• Justify why $\angle BDF = \angle BEF$.

• Use the fact that $AF$ and $BE$ are parallel to each other and since you have computed $\angle AFE$ to compute $\angle BEF $