Finding $E[X]$ in two ways where $X$ is the number of white balls selected when balls are chosen at random from an urn

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I do my homework but I understand how to find the probability of this exercise, Could somebody give an idea or detail me.

The problem, let $X$ denote the number of white balls selected when $k$ balls are chosen at random from an urn containing $n$ white and $m$ black balls.

Let, for $i = 1, 2, \ldots, k; j = 1, 2, \ldots , n,$

$X_i=1$ if the $i^{th}$ ball selected is white, $0$ otherwise.

and $Y_i=1$ if the $j^{th}$ white ball is selected, $0$ otherwise.

Compute $E[X]$ in two ways by expressing $X$ first as a function of the $X_i$ ’s and then of the $Y_j$ ’s.

Then, we have to find first $E[X]=E[X_1]+E[X_2]+\cdots+E[X_k]$

and $E[X]=E[Y_1]+E[Y_2]+\cdots+E[Y_n]$.

That my question, how we find each $E[X_i]$ and $E[X_j]$?