I have to following question which I find hard to solve.
Is there a linear transformation from $\mathbb{R}^5$ to $\mathbb{R}^4$ such that:
$T:\mathbb{R}^5→\mathbb{R}^4$
Such that:
$\text{ker}T=\{(x,y,z,w)\in \mathbb{R}^5 \mid x=2y $ and $ z=2t=3w\}$
Define it on a basis of $\mathbb{R}^5$
Now I understand that I need to complete the basis to $\mathbb{R}^5$ with the standard basis, but I don't know how.
From there, after I found that basis, I can prove that a linear transformation exists (and only one, such that $T(Xi)=Yi$.
Your help is appreciated, thank you.
$T(x,y,z,t,w)=(x-2y, z-2t ,z-3w, 2t-3w )$