Finding the Big $\Theta$ of inverse factorial

Question

I'm having trouble finding $g(n)$ such that $f(n)=\Theta(g(n))$ where $f(n)$ is the inverse factorial ( $f(1)=1$ , $f(2)=f(3)=f(4)=f(5)=2$ , $f(6)....f(23)=3$, $f(24)=4$ and so on.) A hint on how to solve this will much be appreciated!