Finding the simplest logically equivalent formula

Question

For the below python statement: [redacted] I am meant to find the simplest logically equivalent formula. That is...remove a logical connectives such as not, and, or while still making the formula logically equivalent as the one given.

So I plugged in the above formula to a python file and gave it some values (range from -5 to 5). This is the code:

print("------default question---------")

def range1(start, end):
        return range(start, end+1)

for y in range1 (-5,5):
    if ~([redacted]):
        print(y)
    else:
        print("{} and {}".format("Missed", y))

And I got these numbers:

-5
-4
-3
-2
-1
0
1
2
3
4
5

The first thing that I did from here was to remove the NOT symbol and flip all the logical operators.

So this is the transformed code:

print("------opposite of question---------")

def range1(start, end):
        return range(start, end+1)

for y in range1 (-5,5):
    if ([redacted])):
        print(y)
    else:
        print("{} {}".format("Missed", y))

which gave me the result:

-5
-4
-3
-2
-1
0
Missed 1
Missed 2
Missed 3
Missed 4
Missed 5

I've tried various test cases but to no avail, I was getting more confused from this small problem.

Would love if someone could point me in the right direction. Cheers :)

Answer 1

At the original statement, you are checking the numbers y <= 1 for divisibility by 2: y <= 1 & y % 2 == 0 - you can not just change the inequality to y > 1 and leave the divisibility check like this y > 1 & y % 2 != 0, because that is now checking other numbers. Not to mention, that & should also be a | by your logic, but that still doesn't fix the problem of checking other numbers.