This post gives
$$\cos A+\cos B+\cos C=1+4\sin \frac {A}{2}\sin \frac {B}{2}\sin \frac {C}{2}$$
Is it possible to derive a generalised formula for
$$\cos A+\cos B+\cos C+...+\cos N$$
i.e., a formula for summing an arbitrary number $n$ of $\cos$ functions? Perhaps something along the lines of
$$\cos A+\cos B+\cos C+...+\cos N=1+(n+1)\sin \frac {A}{2}\sin \frac {B}{2}\sin \frac {C}{2}...\sin \frac {N}{2}$$
But that's just a wild guess, and I'd have no idea how to prove it.
It doesn't seem true in general, let try with some numerical value to disprove that.
For this special case we can refer to Lagrange's trigonometric identities
$$\sum_{n=1}^N \cos (n\theta) = -\frac{1}{2}+\frac{\sin\left(\left(N+\frac{1}{2}\right)\theta\right)}{2\sin\left(\frac{\theta}{2}\right)}$$