Fourier transform of a convolution - differentiabilty

157 Views Asked by At

I am not sure how to prove this property of Fourier transforms:

Two functions that have compact support and are continuous $ f, g \in C_c(\mathbb R)$ and therefore the Fourier transform of their convolution is infintely differentiable, $$ \widehat {f*g} \in C^\infty(\mathbb R).$$

I tried writing the whole integral down - but I think that I am missing a certain property of functions with compact support. Any tip/idea on how to approach this problem is welcome.

1

There are 1 best solutions below

0
On BEST ANSWER

By the Paley-Wiener theorem, the Fourier transform of a continuous and compact-supported function is much more than $C^\infty$: it is an entire function with finite order. The space of such functions is closed with respect to $\cdot$ and $\widehat{f*g}=\widehat{f}\cdot \widehat{g}$.