Q. Three coins are tossed simultaneously 100 times with the following frequencies of different outcomes:
If the three coins are simultaneously tossed again, compute the compute the probability of :
(i) 2 heads coming up.
If I consider gambler's fallacy, answer of (i) should be $\frac{3}{8}$.
But, the solution I got from internet says, the probability of event (i) = $\frac{36}{100}$.
Here is a link to the solution: https://byjus.com/question-answer/three-coins-are-tossed-simultaneously-100-times-with-the-following-frequencies-of-different-outcomes-begin/
Why gambler's fallacy hasn't been considered in the above solution?