Let's say the life time $\tau$ of a particle to exist with a given velocity $v$ is given by
$\tau \sim \frac{1}{1+v^2}$
The maximum velocity is $U$.
I want to know the probability of finding the particle in velocity range $(0-v)$. I know I need to find the PDF for given relation but I am not sure how to achieve that. The steps I am following are:
- Find total area under function.
- Divide function by total area to make it's integral converge to 1.
I don't know how to proceed after this. Any help/hint is highly appreciated.
Assuming that the velocity is uniformly disributed in the interval $[0;u]$ and given the tranformation that maps from the velocity $v$ to the lifetime $\tau$, the pdf of the lifetime results to me
$$f_{T}(t)=\frac{1}{2u t\sqrt{t(1-t)}}\mathbb{1}_{\Big[\frac{1}{1+u^2};1\Big]}(t)$$
This has been obtained using the Fundamental Transformation Theorem (paragraph 2 in the enclosed link)
$$f_T(t)=f_V[g^{-1}(t)]\Big|\frac{d}{dt}g^{-1}(t)\Big|$$
Where
$$f_V(v)=\frac{1}{u}\mathbb{1}_{[0;u]}(v)$$
$t=\frac{1}{1+v^2}$