We have the following relations: $$x+y+z = 180^\circ \tag 1$$ $$ x = \frac{y + 100^\circ}{2} \tag 2$$ $$z = \frac{3y -100^\circ}{2} \tag 3$$
Can you find $x,y,z$ from $(1)\, , (2)\, , (3)?$
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we get three equations
$$2x-y=100^{\circ}$$
$$3y-2z=100^{\circ}$$
$$x+y+z=180^{\circ}$$
can you solve this System?
solving this System we get $$80^{\circ},60^{\circ},40^{\circ}$$
Hint:
We have the following relations: $$x+y+z = 180^\circ \tag 1$$ $$ x = \frac{y + 100^\circ}{2} \tag 2$$ $$z = \frac{3y -100^\circ}{2} \tag 3$$
Can you find $x,y,z$ from $(1)\, , (2)\, , (3)?$