Give an example of function which is bounded on [a,b] but not Riemann integrable on [a.b].

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Unable to find the function which is bounded but not Riemann integrable.

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You need a highly discontinuous function. The classical example is $$ f(x)=\cases{0& if $x\in\Bbb Q$\\1& if $x\notin \Bbb Q$} $$

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Take any nice function, like $f(x) = 1$ or $f(x) = x$ and have it take different values on the irrationals. This almost always works for this type of thing. This is (AFAIK) what bothers people about the Riemann integral.

$$f(x) = 1$$ if $x$ is rational and $$f(x) = 0$$ otherwise.