Given $g$ find an $f$ which is solution for $L f = g$. How do I do this?

143 Views Asked by At

I am learning about Stochastic processes. To characterize uniqueness of solutions to a given Stochastic differential equation, I need to find for each continuous function $g :\Bbb{R}^2_+ \to \Bbb{R}$ a function $f:\Bbb{R}^2_+ \to \Bbb{R}$ such that

$$ -\gamma f + (\partial_x f) (y-x) + (\partial_y f) (x-y) + \frac{1}{2} \bigg((\partial_{xx} f) x + (\partial_{yy} f) y\bigg) = g $$

This is I believe an inverse problem which has to do with spectral techniques such as proving that $\gamma \in \rho(L)$ where

$$L f = (\partial_x f) (y-x) + (\partial_y f) (x-y) + \frac{1}{2} \bigg((\partial_{xx} f) x + (\partial_{yy} f) y\bigg)$$

Maybe this can be solved more straightforwardly by finding a Green's function $G(x,y,\tilde{x}, \tilde{y})$ that satisfies $$ -\gamma G - L G = \delta_{x -\tilde{x}} \delta_{y - \tilde{y}}$$

or something similar and then defining

$$f = G*g. $$

How can we find such an $f$? Does it exist? Is there any good reference on the literature for this subject?


Note: Here $(\partial_x f) (y-x) $ means $(\partial_x f(x,y)) \cdot (y-x)$