A swimming pool in the shape of a rectangular solid is $60$ feet long and $48$ feet wide. The bottom of the swimming pool is horizontal. To raise the water level in the pool by $\frac{1}{4}$ foot, approximately how many gallons of water must be added?($1$ cubic foot = $7.5$ gallons, rounded to the nearest $0.1$ gallon)
This question makes no sense to me, I read it over $10$ times and I'm sure it didn't mention about the height of the pool. If the question means to no providing the height, how do we find the volume? The answer is $5400$, which seems like $\frac{60 \times 48}{4} \times 7.5 = 5400$
I'm not sure what I'm missing here, any help is highly appreciated.