If the MGF of a random variable X is
Mx(t) = $\frac{1}{3t}(e^t-e^{-2t})$ for $t\neq0$
Find the distribution of X.
I am currently blank as to how to approach this, a hint would be appreciated
If the MGF of a random variable X is
Mx(t) = $\frac{1}{3t}(e^t-e^{-2t})$ for $t\neq0$
Find the distribution of X.
I am currently blank as to how to approach this, a hint would be appreciated
Familiarity with common mgf would help.
Suppose $Y\sim [a,b]$,
$$M_Y(t)=E[e^{tY}]=\int_a^b e^{ty} \frac1{b-a}\, dy=\frac{(e^{tb}-e^{ta})}{(b-a)t}$$
Compare with your question and you should be abe to answer the question.