Question

Why can we assume that the range of the generator of a $C_0$ semigroup is already the full space?

score 84 · Answer 1 · 2026-05-06 09:11:36

84

Views

Why can we assume that the range of the generator of a $C_0$ semigroup is already the full space?

Published on 06 May 2026 - 9:11

score 230 · Answer 2 · 2026-04-23 03:34:54

230

Views

What is the closure of the level set of convex function $g(x):R^n\rightarrow R,$ $\{x:g(x)<a\}$.

Published on 23 Apr 2026 - 3:34

score 59 · Answer 3 · 2026-04-23 14:24:07

59

Views

Regular Set of a closed Operator

Published on 23 Apr 2026 - 14:24

score 1.4k · Answer 4 · 2026-04-23 10:25:17

1.4k

Views

Closed graph theorem seems to state that a closed operator has to be bounded?

Published on 23 Apr 2026 - 10:25

score 264 · Answer 5 · 2026-04-23 05:25:26

264

Views

A problem on Closed Graph Theorem

Published on 23 Apr 2026 - 5:25

score 421 · Answer 6 · 2026-04-23 11:40:11

421

Views

Show that Identity is closed but not continuous

Published on 23 Apr 2026 - 11:40

score 124 · Answer 7 · 2026-04-22 20:21:57

124

Views

A linear operator with a closed graph that is not bounded.

Published on 22 Apr 2026 - 20:21

score 168 · Answer 8 · 2026-04-30 11:30:45

168

Views

Closed operator, closed graph

Published on 30 Apr 2026 - 11:30

score 62 · Answer 9 · 2026-04-22 21:17:28

62

Views

About Closed Graph Theorem for conjugate linear map

Published on 22 Apr 2026 - 21:17

score 57 · Answer 10 · 2026-04-22 19:24:34

57

Views

To show Maps are closed .Closed Graph theorem

Published on 22 Apr 2026 - 19:24

score 658 · Answer 11 · 2026-04-23 10:17:25

658

Views

Uniform boundedness principle and closed graph Theorem

Published on 23 Apr 2026 - 10:17

score 129 · Answer 12 · 2026-04-28 14:41:08

129

Views

Pre-composing a Closed operator by a bounded operator

Published on 28 Apr 2026 - 14:41

score 173 · Answer 13 · 2026-04-27 20:11:15

173

Views

functional analysis : problem related to closed graph theorem

Published on 27 Apr 2026 - 20:11

score 187 · Answer 14 · 2026-05-07 03:07:57

187

Views

Showing $x \mapsto B(x,y), y\mapsto B(x,y)$ continuous $\implies B(x,y)\le c\|x\|\|y\|$ for all $x,y\in H$, where $B:H\to H$ sesquilinear, $H$ Hilbert

Published on 07 May 2026 - 3:07

score 117 · Answer 15 · 2026-04-28 10:20:50

117

Views

Show that $\vert \vert \vert \cdot \vert \vert \vert$ is equivalent to $\vert \vert \cdot \vert \vert_{1}$

Published on 28 Apr 2026 - 10:20

List Question

Why can we assume that the range of the generator of a $C_0$ semigroup is already the full space?

What is the closure of the level set of convex function $g(x):R^n\rightarrow R,$ $\{x:g(x)<a\}$.

Regular Set of a closed Operator

Closed graph theorem seems to state that a closed operator has to be bounded?

A problem on Closed Graph Theorem

Show that Identity is closed but not continuous

A linear operator with a closed graph that is not bounded.

Closed operator, closed graph

About Closed Graph Theorem for conjugate linear map

To show Maps are closed .Closed Graph theorem

Uniform boundedness principle and closed graph Theorem

Pre-composing a Closed operator by a bounded operator

functional analysis : problem related to closed graph theorem

Showing $x \mapsto B(x,y), y\mapsto B(x,y)$ continuous $\implies B(x,y)\le c\|x\|\|y\|$ for all $x,y\in H$, where $B:H\to H$ sesquilinear, $H$ Hilbert

Show that $\vert \vert \vert \cdot \vert \vert \vert$ is equivalent to $\vert \vert \cdot \vert \vert_{1}$

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